Question
Solve the following equations for x:
$7^{2\text{x}+3}=1$
$7^{2\text{x}+3}=1$
$\Rightarrow7^{2\text{x}+3}=1$
$\Rightarrow7^{2\text{x}+3}=7^0$
$\Rightarrow2\text{x}+3=0$
$\Rightarrow2\text{x}=-3$
$\Rightarrow\text{x}=-\frac{3}{2}$
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$\Big(\sqrt{\frac{3}{5}}\Big)^{\text{x}+1}=\frac{125}{27}$
$\frac{\sqrt[4]{1250}}{\sqrt[4]{2}}$