Question
Solve the following equations :
$\frac{y-4}{3}+3 y=4$
✓
Answer
$
\begin{aligned}
& \text {} \frac{y-4}{3}+3 y=4 \\
& \therefore \frac{y-4}{3} \times 3+3 y \times 3=4 \times 3
\end{aligned}
$
...[Multiplying both the sides by 3 ]
$
\begin{aligned}
& \therefore y-4+9 y=12 \\
& \therefore 10 y-4=12 \\
& \therefore 10 y-4+4=12+4
\end{aligned}
$
...[Adding 4 on both the sides]
$
\begin{aligned}
& \therefore 10 y=16 \\
& \therefore \frac{10 y}{10}=\frac{16}{10} \ldots[\text { Dividing both the sides by } 10] \\
& \therefore y=\frac{8}{5}
\end{aligned}
$
\begin{aligned}
& \text {} \frac{y-4}{3}+3 y=4 \\
& \therefore \frac{y-4}{3} \times 3+3 y \times 3=4 \times 3
\end{aligned}
$
...[Multiplying both the sides by 3 ]
$
\begin{aligned}
& \therefore y-4+9 y=12 \\
& \therefore 10 y-4=12 \\
& \therefore 10 y-4+4=12+4
\end{aligned}
$
...[Adding 4 on both the sides]
$
\begin{aligned}
& \therefore 10 y=16 \\
& \therefore \frac{10 y}{10}=\frac{16}{10} \ldots[\text { Dividing both the sides by } 10] \\
& \therefore y=\frac{8}{5}
\end{aligned}
$
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