Question
Solve the following equations:
$\sin\text{x}-3\sin2\text{x}+\sin3\text{x}=\cos\text{x}-3\cos2\text{x}+\cos3\text{x}$
$\sin\text{x}-3\sin2\text{x}+\sin3\text{x}=\cos\text{x}-3\cos2\text{x}+\cos3\text{x}$
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| Length of life $($in hours$):$ | $550-650$ | $650-750$ | $750-850$ | $850-950$ | $950-1050$ |
| Factory $A: ($Number of bulbs$)$ | $10$ | $22$ | $52$ | $20$ | $16$ |
| Factory $B: ($Number of bulbs$)$ | $8$ | $60$ | $24$ | $16$ | $12$ |