Question
Solve the following equations using the formula
$2 x^2+7 x+5=0$

Answer

$2 x^2+7 x+5=0$
Here a = 2, b = 7 and c = 5
Then $x=\frac{-b \pm \sqrt{b^2-4 a c}}{2(a)}$
$=\frac{-(7) \pm \sqrt{(7)^2-4(2)(5)}}{2(2)}$
$=\frac{-7 \pm 3}{4}=\frac{-7+3}{4}$
and $\frac{-7-3}{4}$
$=-1$ and $-\frac{5}{2}$

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