Question
Solve the following equations
$2 y+\frac{7}{2}=\frac{35}{2}$
$2 y+\frac{7}{2}=\frac{35}{2}$
✓
Answer
Given, $2 y+\frac{7}{2}=\frac{35}{2}$
On subtracting $\frac{7}{2}$ from both the sides, we get
$2 y+\frac{7}{2}-\frac{7}{2}=\frac{35}{2}-\frac{7}{2}$
$\Rightarrow 2 y=\frac{35-7}{2}$
$2 y=\frac{28}{2}$
Now, on dividing both sides by 2 , we get
$\frac{2 y}{2}=\frac{28}{2 \times 2} \Rightarrow y=\frac{28}{4}$
$\therefore y=7$,
which is the required solution.
On subtracting $\frac{7}{2}$ from both the sides, we get
$2 y+\frac{7}{2}-\frac{7}{2}=\frac{35}{2}-\frac{7}{2}$
$\Rightarrow 2 y=\frac{35-7}{2}$
$2 y=\frac{28}{2}$
Now, on dividing both sides by 2 , we get
$\frac{2 y}{2}=\frac{28}{2 \times 2} \Rightarrow y=\frac{28}{4}$
$\therefore y=7$,
which is the required solution.
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