Question
Solve the following equation:
$\sqrt{2} x ^2-3 x -2 \sqrt{2}=0$

Answer

$\sqrt{2} x^2-3 x-2 \sqrt{2}=0 $
$ x^2-\frac{3}{\sqrt{2}} x-2=0 $
$x^2+\frac{1}{\sqrt{2}} x-2 \sqrt{2}-2=0$
$ x\left(x+\frac{1}{\sqrt{2}}\right)-2 \sqrt{2}\left(x+\frac{1}{\sqrt{2}}\right)=0$
$\left(x+\frac{1}{\sqrt{2}}\right)(x-2 \sqrt{2})=0 $
$\left(x+\frac{1}{\sqrt{2}}\right)=0,(x-2 \sqrt{2})=0$
$x=-\frac{1}{\sqrt{2}}, x=2 \sqrt{2}$

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