Question
Solve the following example.
Speed in first medium, $v_1 = 3 \times 10^8 m/s$
Speed in second medium, $v_2 = 2 \times 10^8 m/s$
Then $_2n_1 = ?$

Answer

Given: Speed of light in first medium $\left( v _1\right)=3 \times 10^8 m / s$,
Speed of light in second medium $\left( v _2\right)=2 \times 10^8 m / s$
To find: Refractive index of the second medium with respect to the first medium $\left({ }_2 n_1\right)$
Formula: ${ }_2 n _1=\frac{ v _1}{ v _2}$
Calculation: From formula,
${ }_2 n _1=\frac{3 \times 10^8}{2 \times 10^8}=1.5$
Refractive index of the second medium with respect to the first medium $\left({ }_2 n_1\right)$ is $1 . 5$.

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