Question
Solve the following for $x$, where $|x|$ is modulus function, $[x]$ is the greatest integer function, $\{x\}$ is a fractional part function.$[x-2]+[x+2]+\{x\}=0$
✓
Answer
$ [x-2]+[x+2]+\{x\}=0$
$\therefore[x]-2+[x]+2+\{x\}=0$
$\therefore[x]+x=0 \ldots \ldots[\{x\}+[x]=x]$
$\therefore x=0$
$\therefore[x]-2+[x]+2+\{x\}=0$
$\therefore[x]+x=0 \ldots \ldots[\{x\}+[x]=x]$
$\therefore x=0$
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