Question
Solve the following for $x$, where $|x|$ is modulus function, $[x]$ is the greatest integer function, $\{x\}$ is a fractional part function.$[\mathrm{x}] 2-5[\mathrm{x}]+6=0$

Answer

$ [x]^2-5[x]+6=0$
$\therefore([x]-3)([x]-2)=0$
$\therefore[x]=3 \text { or } 2$
$\text { If }[x]=2 \text {, then } 2 \leq x<3$
$\text { If }[x]=3 \text {, then } 3 \leq x<4$
$\therefore \text { Solution set }=[2,4) $

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