$ \begin{aligned} & |7 x-4|<10 \\ & -10<7 x-4<10 \ldots . . .[|x|<k \text { is same as }-k<x<k] \end{aligned} $ Adding 4 on both sides, we get $ -6<7 x<14 $ Dividing both sides by 7 , we get $ \begin{aligned} & -\frac{6}{7}<x<\frac{14}{7} \\ & \therefore-\frac{6}{7}<x<2 \end{aligned} $ $\therefore x$ takes all real values between $-\frac{6}{7}$ and 2 . $\therefore$ Solution set $=\left(-\frac{6}{7}, 2\right)$
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