Question
Solve the following linear in-equation and graph the solution set on a real number line:
$3(5x+ 3) \leq 2(9x-17), x \in W$
$3(5x+ 3) \leq 2(9x-17), x \in W$
✓
Answer
$3(5 x+3) \geq 2(9 x-17) $
$15 x+9 \geq 18 x-34 $
$15 x-18 x \geq-34-9 $
$-3 x \geq-43 $
$3 x \leq 43 $
$x \leq \frac{43}{3}$
Solution set $=\left[x \leq \frac{43}{3}\right]$
$15 x+9 \geq 18 x-34 $
$15 x-18 x \geq-34-9 $
$-3 x \geq-43 $
$3 x \leq 43 $
$x \leq \frac{43}{3}$
Solution set $=\left[x \leq \frac{43}{3}\right]$
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