Question
Solve the following linear inequations in R: $\frac{2\text{x}+3}{4}-3<\frac{\text{x}-4}{3}-2$

Answer

$\frac{2\text{x}+3}{4}-3<\frac{\text{x}-4}{3}-2$ $\frac{2\text{x}+3-12}{4}<\frac{\text{x}-4-6}{3}$ 3 (2x + 3 - 12) < 4 (x - 4 - 6) 3(2x - 9) < 4 (x - 10) 6x - 27 < 4x - 40 6x - 4x < -40 + 27 2x < -13 $\text{x}<-\frac{13}{2}$ $\therefore$ The solution set is $\Big(-\infty,-\frac{13}{2}\Big)$

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