Question
Solve the following linear inequations in R: $\frac{3\text{x}-2}{5}\leq\frac{4\text{x}-3}{2}$

Answer

$\frac{3\text{x}-2}{5}\leq\frac{4\text{x}-3}{2}$ $\Rightarrow\frac{3\text{x}}{5}-\frac{2}{5}\leq\frac{4\text{x}}{2}-\frac{3}{2}$ $\Rightarrow\frac{3\text{x}}{5}-\frac{4\text{x}}{2}\leq\frac{-3}{2}+\frac{2}{5}$ $\Rightarrow\frac{3\text{x}}{5}-\frac{4\text{x}}{2}\leq\frac{-3}{2}+\frac{2}{5}$ $\Rightarrow\frac{6\text{x}-20\text{x}}{10}\leq\frac{-15+4}{10}$ $\Rightarrow-14\text{x}\leq-11$ $\Rightarrow14\text{x}\geq11$ $\Rightarrow\text{x}\geq\frac{11}{14}$ $\Big[\frac{11}{14},\infty\Big)$ is the solution set

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