Question
Solve the following linear inequations in R: $\frac{3}{\text{x}-2}<1$

Answer

$\frac{3}{\text{x}-2}<1$ $\frac{3}{\text{x}-2}-1<0$ $\frac{3-(\text{x}-2)}{\text{x}-2}<0$ $\frac{3-\text{x}+2}{\text{x}-2}<0$ $\frac{5-\text{x}}{\text{x}-2}<0$ $\frac{\text{x}-5}{\text{x}-2}>0$ Case1: x - 5 > 0 and x - 2 > 0 ⇒ x > 5 and x > 2 ⇒ x > 5 Case 2: x - 5 < 0 and x - 2 < 0 ⇒ x < 5 and x < 2 ⇒ x < 2 $\therefore$ solution set is $(-\infty,2)\cup(5,\infty)$

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