Question
Solve the following linear inequations in R: $3\text{x}+9\geq-\text{x}+19$

Answer

$3\text{x}+9\geq-\text{x}+19$ $\Rightarrow3\text{x}+\text{x}\geq19-9$ $\Rightarrow4\text{x}\geq10$ $\Rightarrow\text{x}\geq\frac{10}{4}=\frac{5}{2}$ $\therefore\Big[\frac{5}{2},\infty\Big)$ is the solution set.

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