Question
Solve the following linear inequations in R:
$\frac{4+2\text{x}}{3}\geq\frac{\text{x}}{2}-3$

Answer

$\frac{4+2\text{x}}{3}\geq\frac{\text{x}}{2}-3$
$\frac{4+2\text{x}}{3}\geq\frac{\text{x}}{2}-3$
$2(4+2\text{x})\geq3(\text{x}-6)$
$8+4\text{x}\geq3\text{x}-18$
$4\text{x}-3\text{x}\geq-18-8$
$\text{x}\geq-26$
$\therefore$ The solution set is $[-26,\infty)$

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