Solve the following linear inequations in R: x + 5 > 4x - 10 - Vidyadip

Question

Solve the following linear inequations in R: x + 5 > 4x - 10

✓

Answer

x + 5 > 4x - 10 ⇒ x - 4x > -10 - 5 ⇒ -3x > -15 ⇒ 3x < 15 $\Rightarrow\text{x}<\frac{15}{3}=5$ ⇒ x < 5 $\therefore(-\infty,5)$ is the solution set.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "(Each question 2 marks)" from Linear Inequations→Linear Inequations — all question types→MATHS STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Let A = {x : x $\in$ N}, B = {x : x = 2n, n $\in$ N}, C = {x : x = 2n - 1, n $\in$ N} and D = {x : x is a prime natural number}. Find: $\text{A}\cap\text{C}$

Let R be a relation from N to N defined by $\text{R}=\{(\text{a, b}):\text{a, b}\in\text{N and a}=\text{b}^2\}.$ Are the following statement true? $(\text{a, b}):\text{R }\text{for all a}\in\text{N}$

Prove that: $\cos\frac{7\pi}{12}+\cos\frac{\pi}{12}=\sin\frac{5\pi}{12}-\sin\frac{\pi}{12}$

Find the domain and range of the real function f defined by $f(x) = \sqrt {x - 1} $

If $Z_1, z_2, z_3$ are complex numbers such that $|\text{z}_1|=|\text{z}_2|=|\text{z}_3|=\Big|\frac{1}{\text{z}_1}+\frac{1}{\text{z}_2}+\frac{1}{\text{z}_3}\Big|=1,$ then find the value of $|\text{z}_1+\text{z}_2+\text{z}_3|.$

Prove that: $\frac{\sin\text{x}+\sin2\text{x}}{1+\cos\text{x}+\cos2\text{x}}=\tan\text{x}$

Find: The $12^{th}$ term of the G.P. $\frac{1}{\text{a}^3\text{x}^3},\text{ax},\text{a}^5\text{x}^5\dots$

Find the derivative of function (px + q)$\left( {\frac{r}{x} + s} \right)$(it is to be understood that a, b, c, d, p, q, r, and s are fixed non-zero constants and m and n are integers).

Solve the inequality 4x + 3 < 5x + 7 for real x.

Evaluate the following: $\frac{1}{\text{i}^{58}}$