Question
Solve the following LPP using graphical method
$
\begin{array}{cc}
\text { Minimize } & z=3 x+5 y \\
\text { constraints } & x+3 y \geq 3 \\
& x+y \geq 2 \\
& x \geq 0, y \geq 0
\end{array}
$

Answer

self

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Solve the differential equation $\frac{d y}{d x}+y \tan x=y^2 \sec x$.
Maximize $Z =3 x+2 y$ subject to constraints$5 x+2 y \leq 10$ $3 x+5 y \leq 15$ $x \geq 0, y \geq 0$using graphical method.
Solve the differential equation $(x+y) d y+(x-y) d x=0$, given $y =1$ when $x =1$.
If given function is continuous at $x =0$ then write the value of $k$.
$f(x)=\left\{\begin{array}{cl}\frac{\log (1+a x)-\log (1-b x)}{x}, & x \neq 0 \\ k, & x=0\end{array}\right.$
A company manufactures two types of novelty souvenirs made of plywood. Souvenirs of type A require 5 minutes each for cutting and 10 minutes each for assembling. Souvenirs of type B require 8 minutes each for cutting and 8 minutes each for assembling. There are 3 hours 20 minutes available for cutting and 4 hours for assembling. The profit is Rs. 5 each for type A and Rs. 6 each for type B souvenirs. How many souvenirs of each type should be manufactured for maximum profit.
Show that $\int_0^a {f(x)g(x)dx = 2\int_0^a {f(x)dx} } $. If f and g are defined, $f(x) = f(a - x)$ and $g(x) + g(a - x) = 4$
Prove that $\tan ^{-1}\left(\frac{63}{16}\right)=\sin ^{-1}\left(\frac{5}{13}\right)+\cos ^{-1}\left(\frac{3}{5}\right)$
Find shortest distance between lines $l_1$ and $l_2$. The vector equations of lines are $\vec{r}=\overparen{i}+\overparen{j}+\lambda(2 \overparen{i}-\overparen{j}+\overparen{k})$ and $\vec{r}=2 \overparen{i}+\overparen{j}-\overparen{k}+\mu(3 \overparen{i}-5 \overparen{j}+2 \overparen{k})$
$\cos ^{-1} \frac{1-a^2}{1+a^2}+\cos ^{-1} \frac{1-b^2}{1+b^2}=2 \tan ^{-1} x$
Solve the differential equation $\cos ^2 x \frac{d y}{d x}+y=\tan x\left(0 \leq x \leq \frac{\pi}{2}\right)$