Question
Solve the following quadratic equation:$100x^2 - 20x + 1 = 0$
✓
Answer
$100x^2 - 20x + 1 = 0$
$\Rightarrow 100x^2 - 10x - 10x + 1 = 0$
$\Rightarrow 10x(10x - 1) - 1(10x - 1) = 0$
$\Rightarrow (10x - 1)(10x - 1) = 0$
$\Rightarrow (10x - 1)^2 = 0$
$\Rightarrow 10x - 1 = 0$
$\Rightarrow\text{x}=\frac{1}{10}$ (repeated root)
$\Rightarrow 100x^2 - 10x - 10x + 1 = 0$
$\Rightarrow 10x(10x - 1) - 1(10x - 1) = 0$
$\Rightarrow (10x - 1)(10x - 1) = 0$
$\Rightarrow (10x - 1)^2 = 0$
$\Rightarrow 10x - 1 = 0$
$\Rightarrow\text{x}=\frac{1}{10}$ (repeated root)
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