Question
Solve the following quadratic equation:$2x^2 + x - 6 = 0$
✓
Answer
$2x^2 + x - 6 = 0$
$\Rightarrow 2x^2 + 4x - 3x - 6 = 0$
$\Rightarrow 2x(x + 2) - 3(x + 2) = 0$
$\Rightarrow (x + 2)(2x - 3) = 0$
$\Rightarrow x + 2 = 0$ or $2x - 3 = 0$
$\Rightarrow x = -2$ or $\text{x}=\frac{3}{2}$
$\Rightarrow 2x^2 + 4x - 3x - 6 = 0$
$\Rightarrow 2x(x + 2) - 3(x + 2) = 0$
$\Rightarrow (x + 2)(2x - 3) = 0$
$\Rightarrow x + 2 = 0$ or $2x - 3 = 0$
$\Rightarrow x = -2$ or $\text{x}=\frac{3}{2}$
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