Question
Solve the following quadratic equation:$4 - 11x = 3x^2$
✓
Answer
$4 - 11x = 3x^2\Rightarrow 3x^2 + 11x - 4 = 0$
$\Rightarrow 3x^2 + 12x - x - 4 = 0$
$\Rightarrow 3x(x + 4) - 1(x + 4) = 0$
$\Rightarrow (x + 4)(3x - 1) = 0$
$\Rightarrow x + 4 = 0$ $\text{or}$ $3x - 1 = 0$
$\Rightarrow x = -4$ $\text{or}$ $\text{x}=\frac{1}{3}$
Hence, $-4 $and $\frac{1}{3}$ are the roots of the equation $4 - 11x = 3x^2$
$\Rightarrow 3x^2 + 12x - x - 4 = 0$
$\Rightarrow 3x(x + 4) - 1(x + 4) = 0$
$\Rightarrow (x + 4)(3x - 1) = 0$
$\Rightarrow x + 4 = 0$ $\text{or}$ $3x - 1 = 0$
$\Rightarrow x = -4$ $\text{or}$ $\text{x}=\frac{1}{3}$
Hence, $-4 $and $\frac{1}{3}$ are the roots of the equation $4 - 11x = 3x^2$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
→→→→
For what value of k are the roots of the quadratic equation $\text{kx}\big(\text{x}-2\sqrt5\big)+10=0$ real and equal?
→A metallic cone of radius 12cm and height 24cm is melted and made into spheres of radius 2cm each. How many spheres are formed?
A bag contains 3 red and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is not red?
Find the roots of the following equations, if they exist, by applying the quadratic formula:
$x^2 - 4x - 1 = 0$
→$x^2 - 4x - 1 = 0$
Solve the following simultaneous equation.
$49x – 57y = 172; 57x – 49y = 252$
→$49x – 57y = 172; 57x – 49y = 252$
Evaluate the following:
$\text{cosec}^330^\circ\cos60^\circ\tan^345^\circ\sin^290^\circ\sec^245^\circ\cot30^\circ$
→$\text{cosec}^330^\circ\cos60^\circ\tan^345^\circ\sin^290^\circ\sec^245^\circ\cot30^\circ$
$\triangle\text{ABD}$ is a right triangle right-angled at A and $\text{AC}\perp\text{BD}.$ Show that
$\frac{\text{AB}^2}{\text{AC}^2}=\frac{\text{BD}}{\text{DC}}$
→$\frac{\text{AB}^2}{\text{AC}^2}=\frac{\text{BD}}{\text{DC}}$
Find x if distance between points L(x, 7) and M(1, 15) is 10.
Solve: $\text{3x}^2+5\sqrt5\text{x}-10=0$
→