Question
Solve the following quadratic equation:$48x^2 - 13x - 1 = 0$
✓
Answer
$48x^2 - 13x - 1 = 0$
$\Rightarrow 48x^2 - 16x + 3x - 1 = 0$
$\Rightarrow 16x(3x - 1) + 1(3x - 1) = 0$
$\Rightarrow (3x - 1)(16x + 1) = 0$
$\Rightarrow 3x - 1 = 0$ or $16x + 1 = 0$
$\Rightarrow\text{x}=\frac{1}{3}$ or $\text{x}=\frac{-1}{16}$
Hence, $\frac{-1}{16}$ and $\frac{1}{3}$ are the roots of the equation $48x^2 - 13x - 1 = 0$
$\Rightarrow 48x^2 - 16x + 3x - 1 = 0$
$\Rightarrow 16x(3x - 1) + 1(3x - 1) = 0$
$\Rightarrow (3x - 1)(16x + 1) = 0$
$\Rightarrow 3x - 1 = 0$ or $16x + 1 = 0$
$\Rightarrow\text{x}=\frac{1}{3}$ or $\text{x}=\frac{-1}{16}$
Hence, $\frac{-1}{16}$ and $\frac{1}{3}$ are the roots of the equation $48x^2 - 13x - 1 = 0$
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