Download App

Quadratic Equation — Mathematics STD 10 — Question

ICSE BoardEnglish MediumSTD 10MathematicsQuadratic Equation2 Marks
Question
Solve the following quadratic equation by factorisation:
$x^2 - 3x - 10 = 0$
✓

Answer

$x^2 - 3x - 10 = 0$
$\Rightarrow x^2- 5x + 2x - 10 = 0$
$\Rightarrow x(x - 5) + 2(x - 5) = 0$
$\Rightarrow (x - 5) (x + 2) = 0$
$\Rightarrow x - 5 = 0$ or $x + 2 = 0$
$⇒ x = 5$ and $x = -2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "[2 Mark Question Answer]" from Quadratic Equation→Quadratic Equation — all question types→Mathematics STD 10 question papers→ICSE Board STD 10 question papers→ICSE Board question paper generator→

Similar questions

Solve the following inequalities and represent the solution set on a number line:
$-3<-\frac{1}{2}-\frac{2 x}{3}<\frac{5}{6}, x \in R$.
→
If $p-15=0$ and $2 x^2+p x+25=0$;find the values of $x$.
→
If the perimeter of a semi-circular protractor is 36 cm. Find its diameter.
→
Find the reciprocal ratio of e following:
$\frac{1}{45}: \frac{1}{54}$
→
Find the ratio of the following in the simplest fcrm:
$a^4 + b^4$ and $a^3 - b^3$​​​​​​​
→
Proved that $cosec^2(90^\circ - \theta ) - \tan^2 \theta = \cos^2(90^\circ - \theta ) + \cos^2 \theta .$
→
The point (-2, 0) on reflection in a line is mapped to (2, 0) and the point (5, -6) on reflection in the same line is mapped to (-5, -6).

(i) State the name of the mirror line and write its equation.

(ii) State the co-ordinates of the image of (-8, -5) in the mirror line.

→
Find the mean of the natural numbers from $3$ to $12.$
→
Find the G.P. whose first term is $64$ and next term is $32.$
→
Find the sub-triplicate ratio of the following :
$125a^3 : 343b^6$
→