Question
Solve the following quadratic equation by factorization.
2m (m-24) = 50

Answer


$\begin{array}{l}
2 m(m-24)=50 \\
2 m^2-48 m-50=0 \\
\Rightarrow 2 m^2-50 m+2 m-50=0 \\
\Rightarrow 2 m(m-25)+2(m-25)=0 \\
\Rightarrow(2 m+2)(m-25)=0 \\
\Rightarrow 2 m+2=0 \text { or } m-25=0 \\
\Rightarrow m=-1 \text { or } m=25
\end{array}$
Hence, $m =-1$ or $m =25$ are roots of the equation.

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