Question
Solve the following quadratic equation by factorization.
2m (m-24) = 50
2m (m-24) = 50
✓
Answer
$2 m(m-24)=50 $
$2 m^2-48 m-50=0$
$\Rightarrow 2 m^2-50 m+2 m-50=0 $
$\Rightarrow 2 m(m-25)+2(m-25)=0 $
$\Rightarrow(2 m+2)(m-25)=0$
$\Rightarrow 2 m+2=0 \text { or } m-25=0 $
$\Rightarrow m=-1 \text { or } m=25$
Hence, $m =-1$ or $m =25$ are roots of the equation.
$2 m^2-48 m-50=0$
$\Rightarrow 2 m^2-50 m+2 m-50=0 $
$\Rightarrow 2 m(m-25)+2(m-25)=0 $
$\Rightarrow(2 m+2)(m-25)=0$
$\Rightarrow 2 m+2=0 \text { or } m-25=0 $
$\Rightarrow m=-1 \text { or } m=25$
Hence, $m =-1$ or $m =25$ are roots of the equation.
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