Question
Solve the following quadratic equation by factorization.
$x^2-15 x+54=0$
$x^2-15 x+54=0$
✓
Answer
$x^2-15 x+54=0 $
$\Rightarrow x^2-6 x-9 x+54=0$
$\Rightarrow x(x-6)-9(x-6)=0 $
$\Rightarrow(x-6)(x-9)=0 $
$x-6=0 \Rightarrow x=6 $
$x-9=0 \Rightarrow x=9$
Hence, $x =6$ and $x =9$ are roots of the equation.
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