Question
Solve the following quadratic equation by factorization.
x2 + x – 20 = 0

Answer


$\begin{array}{l}
x^2+x-20=0 \\
\Rightarrow x^2+5 x-4 x-20=0 \\
\Rightarrow x(x+5)-4(x+5)=0 \\
\Rightarrow(x+5)(x-4)=0 \\
x+5=0 \Rightarrow x=-5 \\
x-4=0 \Rightarrow x=4 z
\end{array}$
Hence, $x=-5$ and $x=4$ are roots of the equation.

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