Question
Solve the following quadratic equation:$\text{x}^2-3\sqrt3-30=0$
✓
Answer
$\text{x}^2-3\sqrt3-30=0$$\Rightarrow\text{x}^2+5\sqrt3\text{x}-2\sqrt3\text{x}-30=0$
$\Rightarrow\text{x}\big(\text{x}+5\sqrt3\big)-2\sqrt3\big(\text{x}+5\sqrt3\big)=0$
$\Rightarrow\big(\text{x}+5\sqrt3\big)\big(\text{x}-2\sqrt3\big)=0$
$\Rightarrow\text{x}+5\sqrt3=0$ or $\text{x}-2\sqrt3=0$
$\Rightarrow\text{x}=-5\sqrt{3}$ or $\text{x}=2\sqrt3$
$\Rightarrow\text{x}\big(\text{x}+5\sqrt3\big)-2\sqrt3\big(\text{x}+5\sqrt3\big)=0$
$\Rightarrow\big(\text{x}+5\sqrt3\big)\big(\text{x}-2\sqrt3\big)=0$
$\Rightarrow\text{x}+5\sqrt3=0$ or $\text{x}-2\sqrt3=0$
$\Rightarrow\text{x}=-5\sqrt{3}$ or $\text{x}=2\sqrt3$
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