Question
Solve the following quadratic equation:$\text{x}^2+2\sqrt{2}\text{x}-6=0$
✓
Answer
$\text{x}^2+2\sqrt{2}\text{x}-6=0$$\Rightarrow\text{x}^2+3\sqrt{2}\text{x}-\sqrt{2}\text{x}-6=0$
$\Rightarrow\text{x}\big(\text{x}+3\sqrt{2}\big)-\sqrt{2}\big(\text{x}+3\sqrt{2}\big)$
$\Rightarrow\big(\text{x}+3\sqrt{2}\big)\big(\text{x}-\sqrt2\big)=0$
$\Rightarrow\text{x}=-3\sqrt2$ or $\text{x}=\sqrt2$
$\Rightarrow\text{x}\big(\text{x}+3\sqrt{2}\big)-\sqrt{2}\big(\text{x}+3\sqrt{2}\big)$
$\Rightarrow\big(\text{x}+3\sqrt{2}\big)\big(\text{x}-\sqrt2\big)=0$
$\Rightarrow\text{x}=-3\sqrt2$ or $\text{x}=\sqrt2$
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