Question
Solve the following quadratic equation using formula method only :
$2 x+5 \sqrt{3} x+6=0$
$2 x+5 \sqrt{3} x+6=0$
✓
Answer
$2 x+5 \sqrt{3} x+6=0 $
$ a =2 ; b =5 \sqrt{3} ; c =6 $
$ D = b ^2-4 ac $
$ D =(5 \sqrt{3})^2-4(2)(6) $
$ =75-48 $
$ =27$
$x=\frac{-b \pm \sqrt{b^2-4 ac }}{2 a}$
$ x=\frac{-(5 \sqrt{3}) \pm 3 \sqrt{3}}{4}$
$ x=\frac{-(5 \sqrt{3})+3 \sqrt{3}}{4}, x=\frac{-(5 \sqrt{3})-3 \sqrt{3}}{4}$
$ x=\frac{-2 \sqrt{3}}{4}, x=\frac{-8 \sqrt{3}}{4} $
$ x=-\frac{\sqrt{3}}{2}, x=-2 \sqrt{3}$
$ a =2 ; b =5 \sqrt{3} ; c =6 $
$ D = b ^2-4 ac $
$ D =(5 \sqrt{3})^2-4(2)(6) $
$ =75-48 $
$ =27$
$x=\frac{-b \pm \sqrt{b^2-4 ac }}{2 a}$
$ x=\frac{-(5 \sqrt{3}) \pm 3 \sqrt{3}}{4}$
$ x=\frac{-(5 \sqrt{3})+3 \sqrt{3}}{4}, x=\frac{-(5 \sqrt{3})-3 \sqrt{3}}{4}$
$ x=\frac{-2 \sqrt{3}}{4}, x=\frac{-8 \sqrt{3}}{4} $
$ x=-\frac{\sqrt{3}}{2}, x=-2 \sqrt{3}$
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