Question
Solve the following quadratic equation using formula method only :
$x^2 +10x- 8= 0$
$x^2 +10x- 8= 0$
✓
Answer
$x^2+10 x-8=0 $
$ a=1 ; b=10, c=-8 $
$D=b^2-4 a c$
$ =(10)^2-4(1)(-8) $
$ =100+32$
$ =132 $
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} $
$ x=\frac{-10 \pm \sqrt{132}}{2} $
$ x=-\frac{10}{2} \pm \sqrt{\frac{132}{4}} $
$ x=-5+\sqrt{33}, x=-5-\sqrt{33}$
$ a=1 ; b=10, c=-8 $
$D=b^2-4 a c$
$ =(10)^2-4(1)(-8) $
$ =100+32$
$ =132 $
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} $
$ x=\frac{-10 \pm \sqrt{132}}{2} $
$ x=-\frac{10}{2} \pm \sqrt{\frac{132}{4}} $
$ x=-5+\sqrt{33}, x=-5-\sqrt{33}$
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