Question
Solve the following quadratic equation using formula method only
$x^2 - 6x + 4 = 0$
$x^2 - 6x + 4 = 0$
✓
Answer
$x^2-6 x+4=0$
$ a=1 ; b=-6 ; c=4 $
$ D=b^2-4 a c$
$ =(-6)^2-4(1)(4) $
$ =36-16 $
$ =20 $
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
$ x=\frac{6 \pm \sqrt{20}}{2} $
$ x=\frac{6+2 \sqrt{5}}{2}, x=\frac{6-2 \sqrt{5}}{2}$
$ x=3+\sqrt{5}, x=3-\sqrt{5}$
$ a=1 ; b=-6 ; c=4 $
$ D=b^2-4 a c$
$ =(-6)^2-4(1)(4) $
$ =36-16 $
$ =20 $
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
$ x=\frac{6 \pm \sqrt{20}}{2} $
$ x=\frac{6+2 \sqrt{5}}{2}, x=\frac{6-2 \sqrt{5}}{2}$
$ x=3+\sqrt{5}, x=3-\sqrt{5}$
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