Question
Solve the following quadratic equation using formula method only
$15x^2 - 28 = x$

Answer

$15 x^2-28=x $
$ 15 x^2-x-28=x$
$ a=15 ; b=-1 ; c=-28$
$D=b^2-4 a c $
$=(-1)^2-4(15)(-28) $
$=1+1680$
$ =1681$
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} $
$ x=\frac{1 \pm \sqrt{1681}}{30} $
$x=\frac{1+41}{30}, x=\frac{1-41}{30} $
$ x=\frac{42}{30}, x=-\frac{40}{30} $
$x=\frac{7}{5} \quad, x=-\frac{4}{3}$

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