Question
Solve the following quadratic equation using formula method only
$2 x^2-2 \cdot \sqrt{6} x+3=0$
$2 x^2-2 \cdot \sqrt{6} x+3=0$
✓
Answer
$2 x^2-2 \cdot \sqrt{6} x+3=0 $
$ a =2 ; b =-2 \sqrt{6} ; c =3 $
$ D = b ^2-4 ac $
$ =(-2 \sqrt{6})^2-4(2)(3) $
$ =24-24 $
$ =0 $
$ x =\frac{- b \pm \sqrt{ b ^2-4 ac }}{2 a} $
$ x =\frac{-(-2 \sqrt{6}) \pm 0}{2 \times 2} $
$x =\frac{\sqrt{6}}{2}$
$ a =2 ; b =-2 \sqrt{6} ; c =3 $
$ D = b ^2-4 ac $
$ =(-2 \sqrt{6})^2-4(2)(3) $
$ =24-24 $
$ =0 $
$ x =\frac{- b \pm \sqrt{ b ^2-4 ac }}{2 a} $
$ x =\frac{-(-2 \sqrt{6}) \pm 0}{2 \times 2} $
$x =\frac{\sqrt{6}}{2}$
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