Question
Solve the following quadratic equation using formula method only
$\frac{5}{4} x^2-2 \sqrt{5} x+4=0$

Answer

$\frac{5}{4} x^2-2 \sqrt{5} x+4=0$
$ 5 x^2-8 \sqrt{5} x+16=0$
$ a=5 ; b=-8 \sqrt{5} ; c=16$
$D=b^2-4 a c$
$ =(-8 \sqrt{5})^2-4(5)(15)$
$ =40-300 \\ =-260$
$x=\frac{-b \pm \sqrt{b^2-4 ac }}{2 a} $
$ x=\frac{-(-8 \sqrt{5}) \pm \sqrt{-260}}{2 \times 5} $
$ x=\frac{8 \sqrt{5} \pm \sqrt{-260}}{2 \times 5}$
$ x=\frac{4 \sqrt{5}}{5} \quad \text { (Since } \sqrt{-260} \text { is not possible) }$

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