Question
Solve the following quadratic equation:$x^2 + 6x + 5 = 0$
✓
Answer
$x^2 + 6x + 5 = 0$
$\Rightarrow x^2 + 5x + x + 5 = 0$
$\Rightarrow x(x + 5) + 1(x + 5) = 0$
$\Rightarrow (x + 5)(x + 1) = 0$
$\Rightarrow x + 5 = 0 or x + 1 = 0$
$\Rightarrow x = -5 or x = -1$
$\Rightarrow x^2 + 5x + x + 5 = 0$
$\Rightarrow x(x + 5) + 1(x + 5) = 0$
$\Rightarrow (x + 5)(x + 1) = 0$
$\Rightarrow x + 5 = 0 or x + 1 = 0$
$\Rightarrow x = -5 or x = -1$
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