Question
Solve the following quadratic equation: $x^2+6 x+5=0$
✓
Answer
$x^2+6 x+5=0 \Rightarrow x^2+5 x+x+5=0$
$\Rightarrow x(x+5)+1(x+5)=0$
$\Rightarrow(x+5)(x+1)=0$
$\Rightarrow x+5=0 \text { or } x+1=0$
$\Rightarrow x=-5 \text { or } x=-1$
$\Rightarrow x(x+5)+1(x+5)=0$
$\Rightarrow(x+5)(x+1)=0$
$\Rightarrow x+5=0 \text { or } x+1=0$
$\Rightarrow x=-5 \text { or } x=-1$
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