Question
Solve the following quadratic equations by factorisation : 6√3 x² + 7x = √3
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Answer
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$3\text{x}-4\text{y}-1=0$
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→$3\text{x}-4\text{y}-1=0$
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→Find the area of a triangle whose vertices are,
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→$(\text{at}_1^2, 2\text{at}_1), (\text{at}_2^2, 2\text{at}_2)$ and $(\text{at}_3^2, 2\text{at}_3).$
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Prove the following identities:
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Prove the following identities:
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→$\frac{\sin\theta-\cos\theta}{\sin\theta+\cos\theta}+\frac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=\frac{2}{\big(2\sin^2\theta-1\big)}$