Question
Solve the following quadratic equations by factorization:
(2x + 3)(3x - 7) = 0
(2x + 3)(3x - 7) = 0
✓
Answer
We have been given
(2x + 3)(3x - 7) = 0
Therefore,
(2x + 3) = 0
2x = -3
$\text{x}=\frac{-3}{2}$
or (3x - 7) = 0
3x = 7
$\text{x}=\frac{7}{3}$
Therefore, $\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{7}{3}$
(2x + 3)(3x - 7) = 0
Therefore,
(2x + 3) = 0
2x = -3
$\text{x}=\frac{-3}{2}$
or (3x - 7) = 0
3x = 7
$\text{x}=\frac{7}{3}$
Therefore, $\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{7}{3}$
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