Question
Solve the following quadratic equations by factorization:
$2x^2 + ax - a^2 = 0$
$2x^2 + ax - a^2 = 0$
✓
Answer
$2x^2 + ax - a^2 = 02x^2 + 2ax - ax - a^2 = 0$
$2x(x + a) - a(x + a) = 0$
$(x + a)(2x - a) = 0$
$x + a = 0 or 2x - a = 0$
$x = -a$ or $\text{x}=\frac{\text{a}}{2}$
Alternate Answer
First calculate $D=b^2-4 a c$
Then apply $x =\frac{- b \pm \sqrt{ D }}{2 a }$
We get $x=-a, x=\frac{a}{2}$
$2x(x + a) - a(x + a) = 0$
$(x + a)(2x - a) = 0$
$x + a = 0 or 2x - a = 0$
$x = -a$ or $\text{x}=\frac{\text{a}}{2}$
Alternate Answer
First calculate $D=b^2-4 a c$
Then apply $x =\frac{- b \pm \sqrt{ D }}{2 a }$
We get $x=-a, x=\frac{a}{2}$
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