Question
Solve the following quadratic equations by factorization:
$\frac{\text{x}-2}{\text{x}-3}+\frac{\text{x}-4}{\text{x}-5}=\frac{10}{3},$ $\text{x}\neq3,5$
$\frac{\text{x}-2}{\text{x}-3}+\frac{\text{x}-4}{\text{x}-5}=\frac{10}{3},$ $\text{x}\neq3,5$

