The given simultaneous equations are$3 x+y=10$$\therefore \quad y=10-3 x$
$x-y=2$$\therefore \quad y=x-2$
The two lines intersect at point (3, 1).∴ x = 3 and y = 1 is the solution of the simultaneous equations 3x + y = 10 and x – y = 2.
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