Question
Solve the following simultaneous equation.
2x – 3y = 9; 2x + y = 13
2x – 3y = 9; 2x + y = 13
✓
Answer
$\begin{aligned}
& 2 x-3 y=9 \dots (1) \\
& 2 x+y=13 \dots (2)
\end{aligned}$
Change the sign of Eq. (II)
$\begin{gathered}
2 x-3 y=9 \\
\frac{-2 x-y=-13}{-4 y=4} \\
y=\frac{4}{4} \\
y=1
\end{gathered}$
Substituting $y=1$ in Eq. (II)
$\begin{aligned}
& 2 x+1=13 \\
& 2 x=13-1 \\
& 2 x=12 \\
& x=6
\end{aligned}$
$\therefore$ solution is $(x, y)=(1,6)$
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