Question
Solve the following simultaneous equation.
2x – 3y = 9; 2x + y = 13

Answer

$2x-3y=9\dots(I)$
$2x+y=13\dots(II)$
Change the sign of Eq. (II)
$2x-3y=9$
$-2x+y=13$
$------$
$-4y=4$
$y=\frac{4}{4}$
$y= 1$
Substituting y = 1 in Eq. (II)
$2x +1 =13$
2x = 13 - 1
2x = 12
x = 6
∴ solution is (x, y) = (1,6)

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