Question
Solve the following simultaneous equation.
3a + 5b = 26; a + 5b = 22

Answer


$\begin{aligned}
& 3 a+5 b=26 \ldots(1) \\
& a+5 b=22 \ldots(2)
\end{aligned}$
Change the sign of Eq. (II)
$\begin{aligned}
& 3 a+5 b=26 \\
& -a-5 b=-22 \\
& 2 a=4 \\
& a=\frac{4}{2} \\
& a=2
\end{aligned}$
Substituting a = 2 in Eq. (II)
$\begin{aligned}
& 2+5 b=22 \\
& 5 b=22-2 \\
& 5 b=20 \\
& b=\frac{20}{5} \\
& b=4
\end{aligned}$
$\therefore$ solution is $(a, b)=(2,4)$

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