Question
Solve the following simultaneous equation.
$3a + 5b = 26; a + 5b = 22$
$3a + 5b = 26; a + 5b = 22$
✓
Answer
$3 a+5 b=26 \ldots \text { (I) }$
$a+5 b=22 \ldots \text { (II) }$
Change the sign of Eq. (II)
$3 a+5 b=26 $
$-a-5 b=-22$
$2 a=4 $
$a=\frac{4}{2}$
$a=2$
Substituting a $=2$ in Eq. (II)
$2+5 b=22 $
$5 b=22-2 $
$5 b=20 $
$b=\frac{20}{5} $
$b=4$
$\therefore$ solution is $(\mathrm{a}, \mathrm{b})=(2,4)$
$a+5 b=22 \ldots \text { (II) }$
Change the sign of Eq. (II)
$3 a+5 b=26 $
$-a-5 b=-22$
$2 a=4 $
$a=\frac{4}{2}$
$a=2$
Substituting a $=2$ in Eq. (II)
$2+5 b=22 $
$5 b=22-2 $
$5 b=20 $
$b=\frac{20}{5} $
$b=4$
$\therefore$ solution is $(\mathrm{a}, \mathrm{b})=(2,4)$
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