Question
Solve the following simultaneous equation.
5m – 3n = 19; m – 6n = –7
5m – 3n = 19; m – 6n = –7
✓
Answer
$\begin{aligned}
& 5 m-3 n=19 \ldots (1) \\
& m-6 n=-7 \ldots (2)
\end{aligned}$
Multiply Eq. II by 5
$5 m-30 n=-35 \ldots (3)$
equating (I) and (III), change the sign of Eq. (III)
$\begin{aligned}
& 5 m -3 n =19 \\
& -5 m +30 n =35\text { Adding both we get } \\
& \Rightarrow 27 n =54
\end{aligned}$
$\begin{aligned}
\Rightarrow n=\frac{54}{27} \\
\Rightarrow n=2
\end{aligned}$
Substituting n = 2 in Eq 1
⇒ 5m - 3(2) = 19
⇒ 5m - 6 = 19
⇒ 5m = 25
⇒ m = 5
∴ Solution is (m , n) = (5, 2)
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