Question
Solve the following simultaneous equation.
5m – 3n = 19; m – 6n = –7

Answer


$5 m-3 n =19 \ldots \text { (I) } $
$m -6 n =-7 \ldots \text { (II) } $
$\text { Multiply Eq. II by } 5 $
$5 m-30 n =-35 \ldots \text { (III) } $
$\text { equating (II) and (III), change the sign of Eq. (III) } $
$5 m-3 n =19 $
$-5 m+30 n =35 $
$\text { Adding both we get } $
$\Rightarrow 27 n =54 $
$\Rightarrow n =\frac{54}{27}$
⇒ n = 2
Substituting n = 2 in Eq 1
⇒ 5m - 3(2) = 19
⇒ 5m - 6 = 19
⇒ 5m = 25
⇒ m = 5
∴ Solution is (m , n) = (5, 2)

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