Question
Solve the following simultaneous equation.
$\frac{2}{x}-\frac{3}{y}=15 ; \frac{8}{x}+\frac{5}{y}=77$

Answer

$\frac{2}{x}-\frac{3}{y}=15$
$\frac{8}{x}+\frac{5}{y}=77$
Let $\frac{1}{x}=m$ and $\frac{1}{y}=n$
$2 m-3 n =15 \ldots (I)$
$8 m+5 n =77 \ldots (II)$
Multiply Eq. $1$ by $4$
$8 m-12 n =60 \ldots (III)$
Equating Eq. $II$ and $III$. Change the signs of Eq. $III$
$8 m+5 n=77$
$\frac{-8 m+12 n=-60}{17 n=17}$
$n=\frac{17}{17}$
$n=1$
Substituting $n =1$ in Eq. $II$
$8 m+5 \times 1=77$
$8 m+5=77$
$8 m=77-5$
$8 m=72$
$m=\frac{72}{8}$
$m=9$
$\therefore m =\frac{1}{ x } \Rightarrow \frac{1}{ x }=9 \Rightarrow x =\frac{1}{9}$
$\therefore n =\frac{1}{ y } \Rightarrow \frac{1}{ y }=1 \Rightarrow y =1$
Hence $( x , y )=\left(\frac{1}{9}, 1\right)$

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