Question
Solve the following system of equations graphically:
2x - 3y + 13 = 0,
3x - 2y + 12 = 0
2x - 3y + 13 = 0,
3x - 2y + 12 = 0
✓
Answer
$\text{2x}-\text{3y}+13=0$ $\Rightarrow\text{y}=\frac{13+\text{2x}}{3}$
$\text{3x}-\text{2y}+12=0$ $\Rightarrow\text{y}=\frac{\text{12}+\text{3x}}{2}$
Since the two graph intersect at (-2, 3), x = -2 and y = 3
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x:
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1
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4
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y:
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5
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7
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x:
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0
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-4
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y:
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6
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0
|
Since the two graph intersect at (-2, 3), x = -2 and y = 3
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